Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.3 Exercises - Page 938: 89

Answer

$P=\displaystyle \frac{mRT}{V} ,\qquad V=\displaystyle \frac{mRT}{P},\qquad T=\displaystyle \frac{PV}{mR}$ For $\displaystyle \frac{\partial P}{\partial T}$, T is the variable, all other variables are treated as constants. $\displaystyle \frac{\partial P}{\partial T}=\frac{\partial}{\partial T}[\frac{mRT}{V}]=\frac{mR}{V}$ For $\displaystyle \frac{\partial \mathrm{V}}{\partial T}$, T is the variable, all other variables are treated as constants. $\displaystyle \frac{\partial V}{\partial T}=\frac{\partial}{\partial T}[\frac{mRT}{P}]=\frac{mR}{P}$ $T\displaystyle \frac{\partial P}{\theta T}\frac{\partial V}{\partial T}=T\cdot\frac{mR}{V}\cdot\frac{mR}{P}=\frac{PV}{mR}\cdot\frac{mR}{V}\cdot\frac{mR}{P}=mR,$ which is what was needed to be shown.

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