Answer
a plane:
Work Step by Step
1. No y in the equation, no intercept with the y-axis.
2. Set $y=0$. The trace is a line ($z=2-x$). Find intercepts with the y and z-axes.
$f(0,0)=2$, so the z intercept is at $(0,0,2)$
When $z=f(x,y)=0$,
$0=2-x$
$x=2$. so the $x$-intercept is at $(2,0,0).$
3. Sketch a line through the intercepts (in the $xz$ plane),
4. Sketch lines through the intercepts, parallel to $y$
5. The result is a plane.
