Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.1 Exercises - Page 913: 17

Answer

Domain = $\{(x,y)|-1\leq x\leq 1\quad$and$\quad -1\leq y\leq 1\}$ (see image)

Work Step by Step

Because of the restrictions for square roots, f is defined when $ 1-x^{2}\geq 0\qquad$and$\qquad 1-y^{2}\geq 0.$ $ x^{2}\leq 1\qquad$and$\qquad y^{2}\leq 1$ $-1\leq x\leq 1\qquad$and$\qquad -1\leq y\leq 1$ This is the region inside a square in $\mathbb{R}^{2}$, sides included (the signs are $\leq$), so we use solid lines. Domain = $\{(x,y)|-1\leq x\leq 1\quad$and$\quad -1\leq y\leq 1\}$ (see image)
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