Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.4 Exercises - Page 838: 9

Answer

$(i \times j) \times k=0$

Work Step by Step

Cross product of a vector with itself is zero. We are given $(i \times j) \times k$ But $ i \times j =k$ Thus, $(k) \times k =0$ Hence, $(i \times j) \times k=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.