Answer
FALSE
Work Step by Step
To use the comparison test, we would need that $a_{n} \geq 0$ be greater than the nth term of a divergent series or smaller than the nth term of a convergent series.
From the given statement, we know $a_{n} \leq b_{n}$, but $\Sigma b_{n}$ is divergent. Therefore, we cannot draw any conclusions on the convergence/divergence of $\Sigma a_{n}$.
