Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - Problems Plus - Page 805: 1

Answer

$\frac{15!}{5!}=6\times 7\times 8........\times 15=10,897,286,400$

Work Step by Step

Consider the Taylor series $sinx=x-\frac{1}{3!}x^3+\frac{1}{5!}x^5-.....$ Thus, $sinx^3=x^3-\frac{1}{3!}x^9+\frac{1}{5!}x^15-.....$ $f^{15}(0)=(sin(x^{3})^{15}(0)=\frac{1}{5!}15!$ Hence, $\frac{15!}{5!}=6\times 7\times 8........\times 15=10,897,286,400$
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