Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.5 Exercises - Page 755: 28

Answer

$0.9856$

Work Step by Step

Given: the series $\Sigma_{n=1}^\infty \dfrac{(-1)^{n+1}}{n^6}$ $S_1=\Sigma_{n=1}^\infty \dfrac{(-1)^{n+1}}{n^6}=\Sigma_{n=1}^3 \dfrac{(-1)^{n+1}}{n^6} \approx 9.85747$ $S_2=\Sigma_{n=1}^\infty \dfrac{(-1)^{n+1}}{n^6}=\Sigma_{n=1}^4 \dfrac{(-1)^{n+1}}{n^6} \approx 9.85502$ $S_3=\Sigma_{n=1}^\infty \dfrac{(-1)^{n+1}}{n^6}=\Sigma_{n=1}^5 \dfrac{(-1)^{n+1}}{n^6} \approx 9.85567$ $S_4=\Sigma_{n=1}^\infty \dfrac{(-1)^{n+1}}{n^6}=\Sigma_{n=1}^6 \dfrac{(-1)^{n+1}}{n^6} \approx 9.85545$ When approximated up to four decimals, our answer is: $0.9856$
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