Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.3 Exercises - Page 745: 29

Answer

Convergent for $p\gt 1$

Work Step by Step

For $p\gt 1$ $\int_{2}^{\infty}\frac{1}{x(lnx)^{p}}dx=[\frac{1}{(1-p)(lnx)^{p-1}}]_{2}^{\infty}$ $=\frac{1}{(1-p)(ln\infty)^{p-1}}-\frac{1}{(1-p)(ln2)^{p-1}}$ $=\frac{1}{-\infty}-\frac{1}{(1-p)(ln2)^{p-1}}$ $=-\frac{1}{(1-p)(ln2)^{p-1}}$ Converges by p-series for $p\gt 1$
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