Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.2 Exercises - Page 736: 56

Answer

$7.1234512345... = \frac{237446}{33333}$

Work Step by Step

$7.1234512345...$ $= 7 + \frac{12345}{10^{5}}+ \frac{12345}{10^{10}}+ \frac{12345}{10^{15}}+...$ $= 7+ \Sigma^{\infty}_{n=0} + \frac{12345}{10^{5}} (\frac{1}{10^{5}})^{n}$ $a=\frac{12345}{105}$ and $r=\frac{1}{105}$ $7.1234512345... = 7 + \frac{\frac{12345}{10^{5}}}{1-\frac{1}{10^{5}}}$ $= 7 + \frac{12345}{99999}$ $= 7 + \frac{4115}{33333}$ $= \frac{237446}{33333}$
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