Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - Review - Exercises - Page 710: 28

Answer

$\dfrac{81}{20}$

Work Step by Step

$Area,A=\int_{t=-2}^{t=1}ydx$ and $dx=3t^2-3dt$ $A=3\int_{-2}^{1}(t^2+t+1)(t^2-1)dt$ $A=3[\frac{1}{5}t^5+\frac{1}{4}t^4-\frac{1}{2}t^2-t]_{-2}^{1}$ $A=\dfrac{81}{20}$
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