Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - 10.6 Exercises - Page 708: 1

Answer

$$r = \frac 4 {2 + cos(\theta)}$$

Work Step by Step

1. Determine the equation that we are going to use: Since the directrix is defined by $x = 4$, we are going to use $cos(\theta)$ in the formula. Since $4$ is positive, the formula will have "$+cos(\theta)$": $$r = \frac{ed}{1 + ecos(\theta)}$$ 2. Substitute the given values for $d$ (directrix) and e (eccentricity): $$r = \frac{\frac 12 (4)}{1 + \frac 12 cos(\theta)} = \frac {2}{1 + \frac 12 cos(\theta)}$$ In order to eliminate the fraction, we should multiply the fraction by $\frac 2 2$: $$r = \frac {2}{1 + \frac 12 cos(\theta)} \times \frac 22 $$ $$r = \frac 4 {2 + cos(\theta)}$$
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