Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Section 8.4 - Measures of Dispersion - Exercises - Page 589: 9

Answer

Standard deviation equals 1.22

Work Step by Step

Step 1 Find the expected value of X from the data. which is found by the equation (X)*(p)+(X)*(p) X being the value and p being the probability for this data expected value would by found by (0)*(.5)+(1)*(.2)+(2)*(.2)+(3)*(.1)=.9 Expected value of X is .9 Step 2 to find the variance the equation is $(x1-E(X))^2*(p1)+(x2-E(X))^2*(p2)$ where x is the data E(X) is the expected value and p is the probability so the equation would be $(0-.9)^2*(.5)+(1-.9)^2*(.2)+(2-.9)^2*(.2)+(3-.9)^2*(.1)$ Which equals 1.49 1.49 is the variance Step 3 to find the standard deviation find the square root of the variance $\sqrt 1.49$ Standard deviation equals 1.22
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