Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Section 8.4 - Measures of Dispersion - Exercises - Page 589: 7

Answer

Variance is 13.01 Standard deviation 3.61

Work Step by Step

Step 1 First find the mean of the data set which is found by adding up all the numbers and dividing by the number of numbers. 2.5+-5.4+4.1+-.1+-.1=1 1/5=.2 Mean equals .2 Step 2 Variance is found by the equation $\frac{(s1−M)^2+(s2−M)^2}{N−1}$ Where s is the sample M is the mean and N is the number of samples So the final equation should look like $\frac{(2.5−.2)^2+(-5.4−.2)^2+(4.1−.2)^2+(-.1−.2)^2+(−.1−.2)^2}{5-1}$ Which equals 13.01 13.01 is the variance Step 3 to find the Standard deviation or Sd you take the square root of the variance $\sqrt (13.01)$ Which approximately equals 3.61 The Sd is 3.61
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