Answer
$P(X=3)=C(6,3)*0.4^3*0.6^3=0.27648$
Work Step by Step
The solution is based on the binomial distribution:
$P(X=x)=C(n,x)*p^{x}*q^{n-x}$
If $x=3$, $p=0.4$, $n=6$, then $q=1-0.4=0.6$ and by substituting into the given variables, we get:
$P(X=3)=C(6,3)*0.4^3*0.6^3=0.27648$
