Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.7 - Markov Systems - Exercises - Page 531: 9

Answer

$P=\begin{bmatrix} 1&0&0&0&0&0 \\ 2/3&0&1/3&0&0&0\\0&2/3&0&1/3&0&0\\0&0&2/3&0&1/3&0\\0&0&0&2/3&0&1/3\\0&0&0&0&1&0 \end{bmatrix}$

Work Step by Step

We will write the $ij$th entry of $P$ as the probability of transition from the state $i$ to $j$ as follows: $P_{11}=1\\ P_{21}=\dfrac{2}{3} \\ P_{23}=\dfrac{1}{3} \\ P_{32}=\dfrac{2}{3}\\P_{34}=\dfrac{1}{3}\\ P_{43}=\dfrac{2}{3}\\P_{45}=\dfrac{1}{3}\\P_{54}=\dfrac{2}{3}\\P_{56}=\dfrac{1}{3}\\P_{65}=1$ Therefore, we have: $P=\begin{bmatrix} 1&0&0&0&0&0 \\ 2/3&0&1/3&0&0&0\\0&2/3&0&1/3&0&0\\0&0&2/3&0&1/3&0\\0&0&0&2/3&0&1/3\\0&0&0&0&1&0 \end{bmatrix}$
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