Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.6 - Bayes' Theorem and Applications - Exercises - Page 519: 12

Answer

$0.18$

Work Step by Step

According to Bayes' theorem: $P(R|H)=\dfrac{P(H|R)P(R)}{P(H|R)P(R)+P(H|R')+P(R')}~~~~~~~~(1)$ Here, we have $P(H|R)= 2 \% =0.02 \\ P(R)= \dfrac{1}{10} =0.1 \\ P(H|R')=1 \% =0.01$ Now, we will now use formula (1) and the given data to obtain: $P(R|H)=\dfrac{P(H|R)P(R)}{P(H|R)P(R)+P(H|R')+P(R')}=\dfrac{(0.02)(0.1)}{(0.02)(0.1)+(0.01) (1-0.1)}$ or, $ \approx 0.18$ Thus, we conclude the probability of raining in Spain when there are hurricanes in Hartford is approximately $0.18$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.