Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 507: 35

Answer

Not independent

Work Step by Step

We know that both $A$ and $B$ are independent events when it satisfies the following condition such that $P(A \cap B)=P(A) P(B) ~~~(1)$ Here, $A$ denotes neither die $1$ and $B$ denotes exactly one die is $2$. We can see that $P(A)=\dfrac{n(A)}{n(S)}=\dfrac{25}{36}$ and $P(B)=\dfrac{n(B)}{n(S)}=\dfrac{10}{36}=\dfrac{5}{18}$ Next, we find that there are nine outcomes that can be possible. So, $P(A \cap B)=\dfrac{n(A \cap B)}{n(S)}=\dfrac{8}{36}=\dfrac{2}{9}$ Also, $P(A \cap B)=\dfrac{2}{9}$ and $P(A) P(B)=(\dfrac{25}{36})(\dfrac{5}{18})=\dfrac{125}{648}$ This means that condition (1) is satisfied. So, both $A$ and $B$ are Not independent events.
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