Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 507: 27

Answer

Mutually exclusive

Work Step by Step

Here, both $A$ and $B$ are mutually exclusive events because $A \cap B=0$. This means that both $A$ and $B$ cannot occur at the same time of any event because new skateboard design cannot be both succeeded and failure at the same time. Thus, both $A$ and $B$ are mutually exclusive.
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