Answer
$.08$
Work Step by Step
We know that $P(A|B)=\frac{P(A\cap B)}{P(B)}$
Therefore
$P(A\cap B)=P(A| B)*P(B)=.2*.4=.08$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 506: 3
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