Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 506: 2

Answer

$.5$

Work Step by Step

We know that $P(A|B)=\frac{P(A\cap B)}{P(B)}$ Therefore $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{.3}{.6}=.5$
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