Answer
$.6$
Work Step by Step
Since $A$ and $B$ are independent, $P(A\cap B)=P(A)*P(B)=.3*.6=.18$
We know that $P(B|A)=\frac{P(A\cap B)}{P(A)}$
$P(B|A)=\frac{P(A\cap B)}{P(A)}=\frac{.18}{.3}=.6$
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