Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.4 - Probability and Counting Techniques - Exercises - Page 492: 9

Answer

$\displaystyle \frac{41}{42}$

Work Step by Step

$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$ $n(S)=C(10,5)=252$ $E$ = not all red. In exercise 1, we found P(all red)=$\displaystyle \frac{1}{42}$ S0, $P(E)=1-\displaystyle \frac{1}{42}=\frac{41}{42}$
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