Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.4 - Probability and Counting Techniques - Exercises - Page 492: 6

Answer

$\displaystyle \frac{2}{21}$

Work Step by Step

$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$ $n(S)=C(10,5)=252$ $E$ = ($2$ of 3 greens) AND $(1$ of 4 reds) AND ($1$ of 2 whites) AND ($1$ of 1 purple) $n(E)=C(3,2)\cdot C(4,1)\cdot C(2,1)\cdot C(1,1)=3\cdot 4\cdot 2\cdot 1=24$ $P(E)=\displaystyle \frac{24}{252}=\frac{2}{21}$
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