Chapter 7 - Section 7.4 - Probability and Counting Techniques - Exercises - Page 492: 3

$\displaystyle \frac{7}{9}$

$P(E)=\displaystyle \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$ $n(S)=C(10,5)=252$ $E$ = at least one white $E'$ = no whites (AND 5 of the 8 nonwhites) $n(E')=C(2,0)\cdot C(8,5)=56$ $P(E')=\displaystyle \frac{56}{252}=\frac{2}{9}$ $P(E)=1-P(E')=\displaystyle \frac{7}{9}$