Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.3 - Probability and Probability Models - Exercises - Page 486: 99

Answer

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Work Step by Step

General addition principale $P(A\cup B)=P(A)+P(B)-P(A\cap B)$ Because the events are mutually exclusive, $P(A\cap B)=0$ Therefore $P(A\cup B)=P(A)+P(B)-0=P(A)+P(B)$
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