Answer
$9,880$
Work Step by Step
We have to choose three numbers out of 40.
We can do that in $C(40,3)=9,880$ ways.
There are 9,880 different combinations.
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 439: 73a
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