Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.3 - Decision Algorithms: The Addition and Multiplication Principles - Exercises - Page 427: 55a

Answer

$36$

Work Step by Step

If the first digit is incorrect and the others are correct, there are 9 different codes, because the first digit can be anything but the correct digit. We can say exactly the same if the second, third and fourth digit is incorrect. Therefore $9*4=36$ incorrect codes will open a programmed padlock
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