Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.3 - Decision Algorithms: The Addition and Multiplication Principles - Exercises - Page 424: 31

Answer

$256$

Work Step by Step

A byte consists of eight bits, and a bit can be either a 0 or a 1, that is two choices for each bit. Therefore the number of different bytes (the number of different characters that can be represented) is $2*2*2*2*2*2*2*2=2^8=256$
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