Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 3 - Section 3.1 - Systems of Two Equations in Two Unknowns - Exercises - Page 186: 32

Answer

$\$20$

Work Step by Step

Let $x$ and $y$ be the servings of milk and pure whey respectively then we can write the equations for the given quantities as follows: $32x+24y=640$......eq(1) $240x+100y=3200$......eq(2) We divide eq(1) by $8$ and eq(2) by $20$ to obtain: $4x+3y=80$....eq(3) and $12x+5y=160$.....eq(4) Multiplying eq(3) by $3$ and subtracting eq(4) from it, we obtain: $4y=80$ $\implies y=20$ that is there are $20$ servings of pure whey. Now we plug in $y=20$ in eq(3) to obtain: $4x+3(20)=80$ $\implies x=5$ that is there are $5$ servings of milk. Thus, the cost of milk$=5\times 1.60=\$8$ The cost of pure whey $=20\times 0.6=\$12$ Total cost $=8+12=\$20$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.