Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 3 - Section 3.1 - Systems of Two Equations in Two Unknowns - Exercises - Page 185: 17

Answer

By looking at graph, the solution of the system of equations is approximately the ordered pairs x,y: $(.3,-1.1)$.

Work Step by Step

By looking at graph, the solution of the system of equations is approximately the ordered pairs x,y: $(.3,-1.1)$. If we want to check the solution we can solve the equation: 1) $3.1x-4.5y=6$ 2) $4.5x+1.1y=0$ By multiplying the second equation by $\frac{4.5}{1.1}\approx4.09$, we get: 2) $4.09\times(4.5x+1.1y)=4.09\times0$ 2) $18.405x+4.5y=0$ We can now add equation 2) to equation 1): $3.1x-4.5y+(18.405x+4.5y)=6+0$ $21.505x=6$ $x=\frac{6}{21.505}\approx.3$ By substituting it back into equation 2), we get the value of y: $4.5x+1.1y=0$ $4.5\times.3+1.1y=0$ $1.35+1.1y=0$ $y=-\frac{1.35}{1.1}\approx-1.1$ The solution of the equation is approximately the ordered pairs x,y: $(.3,-1.1)$
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