Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 3 - Section 3.1 - Systems of Two Equations in Two Unknowns - Exercises - Page 185: 12

Answer

Y can be any real number. The function between the x and y is: $x=\frac{1+3y}{2}$

Work Step by Step

1) $2x-3y=1$ 2) $6x-9y=3$ If we multiply the first equation by 3, we get: 1) $3\times(2x-3y)=3\times1$ 1) $6x-9y=3$ Therefore the two equations are equivalent, resulting in: subtracting equation (1) from equation (2): $0=0$ Therefore, y can be any real number. The function between x and y can be given by solving any of the two equations: 1) $2x-3y=1$ $2x=1+3y$ $x=\frac{1+3y}{2}$ By graphing both equations, we expect to have only one line on the graph. See the picture attached.
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