Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 3 - Review - Review Exercises - Page 219: 20

Answer

The object should be at $160 ^o C$, which is equal to $320 ^o F$ $C = 160$ $F = 320$

Work Step by Step

1. Create a unknown that has the value of that temperature, I am going to call it "$T$": - The Celsius temperature is half its Fahrenheit temperature, so: $C = \frac 1 2F$ - I am also going to give $T$ the Celsius temperature value: $T = C$ $T = \frac 1 2 F$ $2T = F$ 2. Substitute these values on the equation that relates Celsius and Fahrenheit temperatures: $5F - 9C = 160$ $5(2T) - 9(T) = 160$ $10 T - 9T = 160$ $T = 160$ 3. Therefore, the object should be at $160 ^o C$, which is equal to $2(160) ^o F$ or $320 ^o F$ $C = T = 160$ $F = 2T = 2(160) = 320$
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