Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 3 - Review - Review Exercises - Page 219: 19

Answer

The object should be at $-40 (^oC \space or \space ^oF)$

Work Step by Step

The equation that relates the Fahrenheit and Celsius temperature scales is: $5F - 9C = 160$ - Since we are looking for the temperature in which $F = C$, we are going to call a third unknown (T) that has exactly this value: $F = C = T$: $5T - 9T = 160$ $-4T = 160$ $\frac {-4T}{-4} = \frac{160}{-4}$ $T = -40$
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