Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 2 - Review - Review Exercises - Page 159: 41

Answer

$231,844 is the largest amount the company can borrow from Industrial Bank.

Work Step by Step

1. Write the formula for the loan borrow value (Present Value): $PV = PMT\frac{1 - (1 +i)^{-n}}{i}$ 2. Identify the values: $PMT = 3,000$ - Monthly payment: m = 12 - 9.5% : r= 0.095 - 10 years : t = 10 i$=r/m=\frac{0.095}{12}$ $n=mt=12 \times 10 = 120$ 3. Substitute the values and calculate the payment: $PV = (3,000)\frac{1 - (1 + \frac{0.095}{12})^{-120}}{\frac{0.095}{12}} = 231,844$
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