Answer
$\$ 8762.11$
Work Step by Step
The present value of an investment earning interest at$\\$
an annual rate of r$=0.0525 \\$
compounded m$=2$ times per year $\\$
for a period of t$=2.5$ years,$\\$
with future value FV$=10,000$ is$\\$
$PV=\displaystyle \frac{FV}{(1+\frac{r}{m})^{mt}} =\displaystyle \frac{10,000}{(1+\frac{0.0525}{ 2})^{ 2(2.5)}}\approx$8762.11264939
