Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Section 1.2 - Functions and Models - Exercises - Page 77: 77

Answer

$f(x)-g(x)\ge 0$ for every x. Therefore the new function will be positive for every x.

Work Step by Step

For every $x$, the value of $f-g$ will be equal to $f(x)-g(x)$. Given the inequality between these functions, we can see that: $f(x)\ge g(x)$ for every x. $f(x)-g(x)\ge 0$ for every x. Therefore the new function will be positive for every x.
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