Answer
$-1, -2, -\frac{3}{2}$
Work Step by Step
$(x+1)(x+2)^{2}+(x+1)^{2}(x+2)=0$
$(x+1)(x+2)((x+1)+(x+2))=0$
$(x+1)(x+2)(2x+3)=0$
$x+1=0, x=-1$
$x+2=0, x=-2$
$2x+3=0, x=-\frac{3}{2}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 6
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