Answer
$\pm \sqrt 2$
Work Step by Step
$x^{4}-4x^{2}=-4$
$x^{4}-4x^{2}+4=0$
$x^{4}-2x^{2}-2x^{2}+4=0$
$(x^{4}-2x^{2})+(-2x^{2}+4)=0$
$x^{2}(x^{2}-2)-2(x^{2}-2)=0$
$(x^{2}-2)(x^{2}-2)=0$
$x^{2}-2=0$
$x^{2}=2$
$x=\pm \sqrt 2$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 3
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