Answer
$x=\frac{2}{3}$
Work Step by Step
$\frac{x-4}{x+1}-\frac{x}{x-1}=0$
$\frac{(x-4)(x-1)-x(x+1)}{(x-1)(x+1)}=0$
$\frac{x^{2}-5x+4-x^{2}-x}{(x-1)(x+1)}=0$
$\frac{-6x+4}{(x-1)(x+1)}=0$
$x=\frac{2}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 23
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