Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Prerequisite Skills Diagnostic Test - Page xxii: 2

Answer

$\frac{51}{35}$

Work Step by Step

In order to subtract fractions with different denominators it is necessary to give them a common denominator In this example the simplest common denominator would be 35 To give both fractions a base multiply each by 1 For $\frac{13}{7}$ multiply by $\frac{5}{5}$: $\frac{13}{7}*\frac{5}{5} = \frac{65}{35}$ For$\frac{2}{5}$ multiply by $\frac{7}{7}$: $\frac{2}{5}*\frac{7}{7} = \frac{14}{35}$ Now because you have given each fraction a common denominator you can subtract normally $\frac{65}{35}-\frac{14}{35}=\frac{51}{35}$
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