Answer
\[ - 20{e^{0.2v}} + C\]
Work Step by Step
\[\begin{gathered}
\int_{}^{} { - 4{e^{0.2v}}dv} \hfill \\
\int_{}^{} {k\,\,f\,\left( x \right)dx = k\int_{}^{} {f\,\left( x \right)dx} } \hfill \\
- 4\int_{}^{} {{e^{0.2v}}dv} \hfill \\
Use\,\,integral\,of\,\,\exp onential\,\,functions \hfill \\
\int_{}^{} {{e^{kx}}dx} = \frac{{{e^{kx}}}}{k} + C \hfill \\
Then \hfill \\
- 4\,\left( {\frac{{{e^{0.2v}}}}{{0.2}}} \right) + C \hfill \\
Simplifying \hfill \\
- 4\,\left( {5{e^{0.2v}}} \right) + C \hfill \\
- 20{e^{0.2v}} + C \hfill \\
\end{gathered} \]
