Answer
$f(g(k)=320k^2+224k+39$
Work Step by Step
In order to find $f(g(k))$ let's find $g(k)$ first:
$g(k) = 8k+3$
Then subsitute in $f(x)$
$f(g(k))=5(8k+3)^2-2(8k+3)=320k^2+224k+39$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 4 - Calculating the Derivative - 4.3 The Chain Rule - 4.3 Exercises - Page 225: 5
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