Answer
$y' = 12x^3-18x^2+\dfrac{1}{4}x$
Work Step by Step
In order to derivate this function you have to apply the power rule:
$\dfrac{d}{dx}(x^n)=nx^{n-1}$
$y' = 3(4)x^3-6(3)x^2+\dfrac{1}{8}(2)x$
$y' = 12x^3-18x^2+\dfrac{1}{4}x$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 4 - Calculating the Derivative - 4.1 Techniques for Finding Derivatives - 4.1 Exercises - Page 207: 3
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