Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.1 Techniques for Finding Derivatives - 4.1 Exercises: 12

Answer

$f'(t) = -14t^{-2}-48t^{-5}$

Work Step by Step

In order to derivate this function you have to apply the power rule: $\dfrac{d}{dx}(x^n)=nx^{n-1}$ But first let's rewrite the function $f(t) = 14t^{-1}+12t^{-4}+\sqrt{2}$ then: $f'(t) = 14(-1)t^{-2}+12(-4)t^{-5}$ $f'(t) = -14t^{-2}-48t^{-5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.