Answer
$\frac{3}{7}$
Work Step by Step
$\lim\limits_{x \to \infty} \frac{3x}{7x -1} =\lim\limits_{x \to \infty} \frac{\frac{3x}{x}}{\frac{7x}{x}-\frac{1}{x}}= \lim\limits_{x \to \infty} \frac{3}{7 - \frac{1}{x}}=\frac{3}{7}$
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