Answer
$x \approx \pm 0.3501$
Work Step by Step
$\ln x + \ln 3x=-1$
$\ln(3x.x)=-1$
means $3x^{2}=e^{-1}$
$x^{2}=\frac{e^{-1}}{3}$
$x \approx \pm 0.3501$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 55
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