Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 53

Answer

$x=5$

Work Step by Step

$\log_{2}(x^{2}-1) - \log_{2}(x+1)=2$ $\log_{2}\frac{x^{2} - 1}{x+1}=2$ $x^{2} -1=2^{2}(x+1)$ $x^{2} - 4x - 5=0$ $x=5$
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