Answer
$x=5$
Work Step by Step
$\log_{2}(x^{2}-1) - \log_{2}(x+1)=2$
$\log_{2}\frac{x^{2} - 1}{x+1}=2$
$x^{2} -1=2^{2}(x+1)$
$x^{2} - 4x - 5=0$
$x=5$
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