Answer
$x=0$
Work Step by Step
$\log(x+5) + \log(x+2)=1$
$\log[(x+5)(x+2)]=1$
$x^{2} + 7x +10=10$
$x^{2}+7x=0$
$x=-7$ and $x=0$ but is -7 not a valid value for x in the original equation, so the only solution is $x=0$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 50
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