Answer
$(2, -1)$
Work Step by Step
$ f(x)=a(x-h)^{2}+k^{2},\qquad$ vertex: (h,k)
(solved as in example 4)
$(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$
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$y=-2x^{2}+8x-9$
$=-2(x^{2}-4x)-9$
$=-2(x^{2}-2\cdot 2\cdot x+4-4)-9$
$=-2(x^{2}-4x+4)-9-(-2)(4)$
$=-2(x-2)^{2}-1$
Vertex: $(2, -1)$.