Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises - Page 55: 70

Answer

Neither.

Work Step by Step

$ f(x)$ is odd if $f(-x)=-f(x)$ $ f(x)$ is even if $f(-x)=f(x)$ ------------- $f(x)=|x-2|$ $f(-x)=|-x-2|=|-(x+2)|=|x+2|$, which does not equal either of $(-f(x))$ or $f(x)$. The function is neither odd nor even.
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